What is the integral from-1 to 1 of 1/(sqrt(x)) ?

The integral from-1 to 1 of 1/(sqrt(x)) is -Does not exist+2

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integral from-1 to 1 of 1/(sqrt(x))

\int_{- 1}^{1} \frac{1}{x} d x

- Does not exist + 2

Solution steps

\int_{- 1}^{1} \frac{1}{x} d x

Adjust integral based on undefined pointsThere is an undefined point within the boundaries at

: 0

= \int_{- 1}^{0} \frac{1}{x} d x + \int_{0}^{1} \frac{1}{x} d x

\int_{- 1}^{0} \frac{1}{x} d x = -

Does not exist

= - Does not exist + \int_{0}^{1} \frac{1}{x} d x

\int_{0}^{1} \frac{1}{x} d x = 2

= - Does not exist + 2

What is the integral from-1 to 1 of 1/(sqrt(x)) ?
The integral from-1 to 1 of 1/(sqrt(x)) is -Does not exist+2