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Popular Calculus >

integral from-1 to 1 of 8x-2

Solution

\int_{- 1}^{1} 8 x - 2 d x

Solution

- 4

Solution steps

\int_{- 1}^{1} 8 x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 8 x d x - \int_{- 1}^{1} 2 d x

\int_{- 1}^{1} 8 x d x = 0

\int_{- 1}^{1} 2 d x = 4

= 0 - 4

Simplify

= - 4

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 8x-2 ?
The integral from-1 to 1 of 8x-2 is -4