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Popular Calculus >

integral from 0 to 1 of (4x^3+5)

Solution

\int_{0}^{1} (4 x^{3} + 5) d x

Solution

6

Solution steps

\int_{0}^{1} 4 x^{3} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x^{3} d x + \int_{0}^{1} 5 d x

\int_{0}^{1} 4 x^{3} d x = 1

\int_{0}^{1} 5 d x = 5

= 1 + 5

Simplify

= 6

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (4x^3+5) ?
The integral from 0 to 1 of (4x^3+5) is 6