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Popular Calculus >

integral from 2 to 9 of (3x+5)

Solution

\int_{2}^{9} (3 x + 5) d x

Solution

\frac{301}{2}

+1

Decimal

150.5

Solution steps

\int_{2}^{9} 3 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{9} 3 x d x + \int_{2}^{9} 5 d x

\int_{2}^{9} 3 x d x = \frac{231}{2}

\int_{2}^{9} 5 d x = 35

= \frac{231}{2} + 35

Simplify

\frac{231}{2} + 35 : \frac{301}{2}

= \frac{301}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 2 to 9 of (3x+5) ?
The integral from 2 to 9 of (3x+5) is 301/2