What is the integral from 0 to 2 of (x^2-10x+16) ?

The integral from 0 to 2 of (x^2-10x+16) is 44/3

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integral from 0 to 2 of (x^2-10x+16)

\int_{0}^{2} (x^{2} - 10 x + 16) d x

\frac{44}{3}

Decimal

14.66666 \dots

Solution steps

\int_{0}^{2} x^{2} - 10 x + 16 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 10 x d x + \int_{0}^{2} 16 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 10 x d x = 20

\int_{0}^{2} 16 d x = 32

= \frac{8}{3} - 20 + 32

Simplify

\frac{8}{3} - 20 + 32 : \frac{44}{3}

= \frac{44}{3}

What is the integral from 0 to 2 of (x^2-10x+16) ?
The integral from 0 to 2 of (x^2-10x+16) is 44/3