y^{''}+81y=sec^2(9x)

Lösung

y^{^{''}} + 81 y = sec^{2} (9 x)

y = c_{1} cos (9 x) + c_{2} sin (9 x) + \frac{- 1 + ln ( tan ( 9 x ) + sec ( 9 x ) ) sin ( 9 x )}{81}

Schritte zur Lösung

y^{''} (x) + 81 y = sec^{2} (9 x)

Solve linear ODE:

y = c_{1} cos (9 x) + c_{2} sin (9 x) + \frac{- 1 + ln ( tan ( 9 x ) + sec ( 9 x ) ) sin ( 9 x )}{81}

y = c_{1} cos (9 x) + c_{2} sin (9 x) + \frac{- 1 + ln ( tan ( 9 x ) + sec ( 9 x ) ) sin ( 9 x )}{81}

s l o p e (\frac{1}{4}, \frac{7}{8}), (4 \frac{1}{4}, 2 \frac{7}{8})

n = 0 \sum \infty \frac{1}{( 2 n + 1 ) ^{6}}

y d x + (1 + x) d y = 0

\frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2} - 7}{x y})

\frac{d x}{d t} + 3 t^{3} x^{5} + \frac{x}{t} = 0