What is the integral from-1 to 3 of (-x^2) ?

The integral from-1 to 3 of (-x^2) is -28/3

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integral from-1 to 3 of (-x^2)

\int_{- 1}^{3} (- x^{2}) d x

- \frac{28}{3}

Decimal

- 9.33333 \dots

Solution steps

\int_{- 1}^{3} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 1}^{3} x^{2} d x

Apply the Power Rule

= - [\frac{x ^{3}}{3}]_{- 1}^{3}

Compute the boundaries:

\frac{28}{3}

= - \frac{28}{3}

What is the integral from-1 to 3 of (-x^2) ?
The integral from-1 to 3 of (-x^2) is -28/3