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Popular Calculus >

integral from 0 to 6 of (x^2-4x)

Solution

\int_{0}^{6} (x^{2} - 4 x) d x

Solution

0

Solution steps

\int_{0}^{6} x^{2} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} x^{2} d x - \int_{0}^{6} 4 x d x

\int_{0}^{6} x^{2} d x = 72

\int_{0}^{6} 4 x d x = 72

= 72 - 72

Simplify

= 0

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 6 of (x^2-4x) ?
The integral from 0 to 6 of (x^2-4x) is 0