What is the integral from pi/2 to pi of 1/(sec(x)) ?

The integral from pi/2 to pi of 1/(sec(x)) is -1

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integral from pi/2 to pi of 1/(sec(x))

\int_{\frac{π}{2}}^{π} \frac{1}{sec ( x )} d x

- 1

Solution steps

\int_{\frac{π}{2}}^{π} \frac{1}{sec ( x )} d x

Rewrite using trig identities

= \int_{\frac{π}{2}}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{\frac{π}{2}}^{π}

Compute the boundaries:

- 1

= - 1

What is the integral from pi/2 to pi of 1/(sec(x)) ?
The integral from pi/2 to pi of 1/(sec(x)) is -1