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Popular Calculus >

integral from 0 to 2 of (8x-x^4)

Solution

\int_{0}^{2} (8 x - x^{4}) d x

Solution

\frac{48}{5}

+1

Decimal

9.6

Solution steps

\int_{0}^{2} 8 x - x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 8 x d x - \int_{0}^{2} x^{4} d x

\int_{0}^{2} 8 x d x = 16

\int_{0}^{2} x^{4} d x = \frac{32}{5}

= 16 - \frac{32}{5}

Simplify

16 - \frac{32}{5} : \frac{48}{5}

= \frac{48}{5}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (8x-x^4) ?
The integral from 0 to 2 of (8x-x^4) is 48/5