What is the integral from-1 to 2 of (x^2-x+2) ?

The integral from-1 to 2 of (x^2-x+2) is 15/2

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integral from-1 to 2 of (x^2-x+2)

\int_{- 1}^{2} (x^{2} - x + 2) d x

\frac{15}{2}

Decimal

7.5

Solution steps

\int_{- 1}^{2} x^{2} - x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{2} d x - \int_{- 1}^{2} x d x + \int_{- 1}^{2} 2 d x

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 2 d x = 6

= 3 - \frac{3}{2} + 6

Simplify

3 - \frac{3}{2} + 6 : \frac{15}{2}

= \frac{15}{2}

What is the integral from-1 to 2 of (x^2-x+2) ?
The integral from-1 to 2 of (x^2-x+2) is 15/2