What is the integral from 1 to t of ln(t) ?

The integral from 1 to t of ln(t) is tln(t)-t+1

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integral from 1 to t of ln(t)

\int_{1}^{t} ln (t) d t

t ln (t) - t + 1

Solution steps

\int_{1}^{t} ln (t) d t

Apply Integration By Parts

= [t ln (t) - \int 1 d t]_{1}^{t}

\int 1 d t = t

= [t ln (t) - t]_{1}^{t}

Compute the boundaries:

t ln (t) - t + 1

= t ln (t) - t + 1

What is the integral from 1 to t of ln(t) ?
The integral from 1 to t of ln(t) is tln(t)-t+1