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Popular Calculus >

integral from 0 to 1 of (x^2+5x)

Solution

\int_{0}^{1} (x^{2} + 5 x) d x

Solution

\frac{17}{6}

+1

Decimal

2.83333 \dots

Solution steps

\int_{0}^{1} x^{2} + 5 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x + \int_{0}^{1} 5 x d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} 5 x d x = \frac{5}{2}

= \frac{1}{3} + \frac{5}{2}

Simplify

\frac{1}{3} + \frac{5}{2} : \frac{17}{6}

= \frac{17}{6}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x^2+5x) ?
The integral from 0 to 1 of (x^2+5x) is 17/6