What is the integral from 0 to 6 of sqrt(x+8) ?

The integral from 0 to 6 of sqrt(x+8) is (28sqrt(14)-32sqrt(2))/3

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integral from 0 to 6 of sqrt(x+8)

\int_{0}^{6} x + 8 d x

\frac{28 14 - 32 2}{3}

Decimal

19.83719 \dots

Solution steps

\int_{0}^{6} x + 8 d x

Apply u-substitution

= \int_{8}^{14} u d u

Apply the Power Rule

= [\frac{2}{3} u^{\frac{3}{2}}]_{8}^{14}

Compute the boundaries:

\frac{28 14 - 32 2}{3}

= \frac{28 14 - 32 2}{3}

What is the integral from 0 to 6 of sqrt(x+8) ?
The integral from 0 to 6 of sqrt(x+8) is (28sqrt(14)-32sqrt(2))/3