What is the integral from-3 to 2 of bx-ax^2 ?

The integral from-3 to 2 of bx-ax^2 is -(5b)/2-(35a)/3

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integral from-3 to 2 of bx-ax^2

\int_{- 3}^{2} b x - a x^{2} d x

- \frac{5 b}{2} - \frac{35 a}{3}

Solution steps

\int_{- 3}^{2} b x - a x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{2} b x d x - \int_{- 3}^{2} a x^{2} d x

\int_{- 3}^{2} b x d x = - \frac{5 b}{2}

\int_{- 3}^{2} a x^{2} d x = \frac{35 a}{3}

= - \frac{5 b}{2} - \frac{35 a}{3}

What is the integral from-3 to 2 of bx-ax^2 ?
The integral from-3 to 2 of bx-ax^2 is -(5b)/2-(35a)/3