What is the integral from 0 to 2pi of-cos(θ) ?

The integral from 0 to 2pi of-cos(θ) is 0

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integral from 0 to 2pi of-cos(θ)

\int_{0}^{2 π} - cos (θ) d θ

0

Solution steps

\int_{0}^{2 π} - cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{2 π} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= - [sin (θ)]_{0}^{2 π}

Compute the boundaries:

0

= - 0

Simplify

= 0

What is the integral from 0 to 2pi of-cos(θ) ?
The integral from 0 to 2pi of-cos(θ) is 0