derivative of (x^2-x+1^{-7})

Lösung

\frac{d}{d x} ((x^{2} - x + 1)^{- 7})

- \frac{7 ( 2 x - 1 )}{( x ^{2} - x + 1 ) ^{8}}

Schritte zur Lösung

\frac{d}{d x} ((x^{2} - x + 1)^{- 7})

Wende die Kettenregel an:

- \frac{7}{( x ^{2} - x + 1 ) ^{8}} \frac{d}{d x} (x^{2} - x + 1)

= - \frac{7}{( x ^{2} - x + 1 ) ^{8}} \frac{d}{d x} (x^{2} - x + 1)

\frac{d}{d x} (x^{2} - x + 1) = 2 x - 1

= - \frac{7}{( x ^{2} - x + 1 ) ^{8}} (2 x - 1)

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{7 ( 2 x - 1 )}{( x ^{2} - x + 1 ) ^{8}}

\int e^{- 3 x} sin (3 x) d x

\frac{\partial}{\partial y} (sin (x - y))

d er i v a t i v e y = - 3 - 2 e^{x}

d er i v a t i v e y = \frac{4}{x - 2}

\int e^{s i n (t)} cos (t) d t