integral from 1 to 2 of (-x^2+x+2)

Lösung

\int_{1}^{2} (- x^{2} + x + 2) d x

\frac{7}{6}

Dezimale

1.16666 \dots

Schritte zur Lösung

\int_{1}^{2} - x^{2} + x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{2} x^{2} d x + \int_{1}^{2} x d x + \int_{1}^{2} 2 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} 2 d x = 2

= - \frac{7}{3} + \frac{3}{2} + 2

Vereinfache

- \frac{7}{3} + \frac{3}{2} + 2 : \frac{7}{6}

= \frac{7}{6}