integral from 1 to x of (t^2)

Lösung

\int_{1}^{x} (t^{2}) d t

\frac{x ^{3} - 1}{3}

Schritte zur Lösung

\int_{1}^{x} t^{2} d t

Wende die Potenzregel an

= [\frac{t ^{3}}{3}]_{1}^{x}

Berechne die Grenzen:

\frac{x ^{3}}{3} - \frac{1}{3}

= \frac{x ^{3}}{3} - \frac{1}{3}

Vereinfache

= \frac{x ^{3} - 1}{3}

\int_{0}^{4} x (4 - x) d x

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