integral from 0 to 6 of sqrt(16-2x)-2

Lösung

\int_{0}^{6} 16 - 2 x - 2 d x

\frac{20}{3}

Dezimale

6.66666 \dots

Schritte zur Lösung

\int_{0}^{6} 16 - 2 x - 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} 16 - 2 x d x - \int_{0}^{6} 2 d x

\int_{0}^{6} 16 - 2 x d x = \frac{56}{3}

\int_{0}^{6} 2 d x = 12

= \frac{56}{3} - 12

Vereinfache

\frac{56}{3} - 12 : \frac{20}{3}

= \frac{20}{3}

\int_{0}^{2} x^{7} 4 - x^{2} d x

\int_{0}^{3} 2 x arctan (x) d x

\int_{2 π}^{5 π} ∣ sin (t) ∣ d t

\int_{0}^{2} ∣ 2 x - 3 ∣ d x

\int_{m}^{\infty} \frac{1}{n ^{6.63}} d n