integral from 0 to 4 of (x^2-4)

Lösung

\int_{0}^{4} (x^{2} - 4) d x

\frac{16}{3}

Dezimale

5.33333 \dots

Schritte zur Lösung

\int_{0}^{4} x^{2} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 4 d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 4 d x = 16

= \frac{64}{3} - 16

Vereinfache

\frac{64}{3} - 16 : \frac{16}{3}

= \frac{16}{3}

\int_{2}^{\infty} \frac{1}{ln ( n )}

\int_{7}^{9} x^{2} + 2 x - 6 d x

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