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Popular Calculus >

y'=y^2-2y

Solution

y^{^{'}} = y^{2} - 2 y

Solution

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

Solution steps

y^{'} (t) = y^{2} - 2 y

Solve Bernoulli ODE:

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y'=y^2-2y ?
The solution for y'=y^2-2y is y= 2/(-e^{2t+c_{1)}+1}