What is the integral from 0 to 1 of sqrt(1x+4) ?

The integral from 0 to 1 of sqrt(1x+4) is (10sqrt(5)-16)/3

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integral from 0 to 1 of sqrt(1x+4)

\int_{0}^{1} 1 x + 4 d x

\frac{10 5 - 16}{3}

Decimal

2.12022 \dots

Solution steps

\int_{0}^{1} 1 \cdot x + 4 d x

Simplify

= \int_{0}^{1} x + 4 d x

Apply u-substitution

= \int_{4}^{5} u d u

Apply the Power Rule

= [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{5}

Compute the boundaries:

\frac{10 5}{3} - \frac{16}{3}

= \frac{10 5}{3} - \frac{16}{3}

Simplify

= \frac{10 5 - 16}{3}

What is the integral from 0 to 1 of sqrt(1x+4) ?
The integral from 0 to 1 of sqrt(1x+4) is (10sqrt(5)-16)/3