What is the integral from 1 to 6 of 4x^3-4x^4-3 ?

The integral from 1 to 6 of 4x^3-4x^4-3 is -4940

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 6 of 4x^3-4x^4-3

\int_{1}^{6} 4 x^{3} - 4 x^{4} - 3 d x

- 4940

Solution steps

\int_{1}^{6} 4 x^{3} - 4 x^{4} - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{6} 4 x^{3} d x - \int_{1}^{6} 4 x^{4} d x - \int_{1}^{6} 3 d x

\int_{1}^{6} 4 x^{3} d x = 1295

\int_{1}^{6} 4 x^{4} d x = 6220

\int_{1}^{6} 3 d x = 15

= 1295 - 6220 - 15

Simplify

= - 4940

What is the integral from 1 to 6 of 4x^3-4x^4-3 ?
The integral from 1 to 6 of 4x^3-4x^4-3 is -4940