What is the integral from infinity to 0 of 1/(3-4x) ?

The integral from infinity to 0 of 1/(3-4x) is diverges

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integral from infinity to 0 of 1/(3-4x)

\int_{\infty}^{0} \frac{1}{3 - 4 x} d x

diverges

Solution steps

\int_{\infty}^{0} \frac{1}{3 - 4 x} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{\infty} \frac{1}{3 - 4 x} d x

\int_{0}^{\infty} \frac{1}{3 - 4 x} d x =

diverges

= diverges

What is the integral from infinity to 0 of 1/(3-4x) ?
The integral from infinity to 0 of 1/(3-4x) is diverges