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Popular Calculus >

integral from 0 to 2 of (e^x-1)

Solution

\int_{0}^{2} (e^{x} - 1) d x

Solution

e^{2} - 3

+1

Decimal

4.38905 \dots

Solution steps

\int_{0}^{2} e^{x} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} e^{x} d x - \int_{0}^{2} 1 d x

\int_{0}^{2} e^{x} d x = e^{2} - 1

\int_{0}^{2} 1 d x = 2

= e^{2} - 1 - 2

Simplify

= e^{2} - 3

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (e^x-1) ?
The integral from 0 to 2 of (e^x-1) is e^2-3