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人気のある微分積分 >

integral from 1 to 2 of (4-x)

解

\int_{1}^{2} (4 - x) d x

解

\frac{5}{2}

+1

十進法表記

2.5

解答ステップ

\int_{1}^{2} 4 - x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 4 d x - \int_{1}^{2} x d x

\int_{1}^{2} 4 d x = 4

\int_{1}^{2} x d x = \frac{3}{2}

= 4 - \frac{3}{2}

簡素化

4 - \frac{3}{2} : \frac{5}{2}

= \frac{5}{2}

グラフ

人気の例

integral from 2 to-2 of x^2-4

\int_{2}^{- 2} x^{2} - 4 d x

integral from-32 to 32 of \sqrt[5]{x^4}

\int_{- 32}^{32} 5 x^{4} d x

integral from 0 to 1 of f(sqrt(1-x))

\int_{0}^{1} f (1 - x) d x

integral from-2 to 2 of (11-|x|^3)

\int_{- 2}^{2} (11 - ∣ x ∣^{3}) d x

integral from 0 to 1 of (-sqrt(1-x^2))

\int_{0}^{1} (- 1 - x^{2}) d x