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Popular Calculus >

integral from 1 to 3 of (9-x^2)

Solution

\int_{1}^{3} (9 - x^{2}) d x

Solution

\frac{28}{3}

+1

Decimal

9.33333 \dots

Solution steps

\int_{1}^{3} 9 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 9 d x - \int_{1}^{3} x^{2} d x

\int_{1}^{3} 9 d x = 18

\int_{1}^{3} x^{2} d x = \frac{26}{3}

= 18 - \frac{26}{3}

Simplify

18 - \frac{26}{3} : \frac{28}{3}

= \frac{28}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 3 of (9-x^2) ?
The integral from 1 to 3 of (9-x^2) is 28/3