What is the integral from 1 to infinity of (ln(n))/n ?

The integral from 1 to infinity of (ln(n))/n is Undefined-(ln(n))/n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to infinity of (ln(n))/n

\int_{1}^{\infty} \frac{ln ( n )}{n}

Undefined - \frac{ln ( n )}{n}

Solution steps

\int_{1}^{\infty} \frac{ln ( n )}{n} d x

Compute the indefinite integral:

\int \frac{ln ( n )}{n} d x = \frac{ln ( n )}{n} x + C

Compute the boundaries:

\int_{1}^{\infty} \frac{ln ( n )}{n} d x =

Undefined

- \frac{1}{n} ln (n)

= Undefined - \frac{1}{n} ln (n)

Simplify

= Undefined - \frac{ln ( n )}{n}

What is the integral from 1 to infinity of (ln(n))/n ?
The integral from 1 to infinity of (ln(n))/n is Undefined-(ln(n))/n