What is the integral from 4 to 7 of (x^2+1/x) ?

The integral from 4 to 7 of (x^2+1/x) is 93+ln(7)-2ln(2)

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integral from 4 to 7 of (x^2+1/x)

\int_{4}^{7} (x^{2} + \frac{1}{x}) d x

93 + ln (7) - 2 ln (2)

Decimal

93.55961 \dots

Solution steps

\int_{4}^{7} x^{2} + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{7} x^{2} d x + \int_{4}^{7} \frac{1}{x} d x

\int_{4}^{7} x^{2} d x = 93

\int_{4}^{7} \frac{1}{x} d x = ln (7) - 2 ln (2)

= 93 + ln (7) - 2 ln (2)

What is the integral from 4 to 7 of (x^2+1/x) ?
The integral from 4 to 7 of (x^2+1/x) is 93+ln(7)-2ln(2)