What is the integral from 0 to 20 of (840-42x) ?

The integral from 0 to 20 of (840-42x) is 8400

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integral from 0 to 20 of (840-42x)

\int_{0}^{20} (840 - 42 x) d x

8400

Solution steps

\int_{0}^{20} 840 - 42 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{20} 840 d x - \int_{0}^{20} 42 x d x

\int_{0}^{20} 840 d x = 16800

\int_{0}^{20} 42 x d x = 8400

= 16800 - 8400

Simplify

= 8400

What is the integral from 0 to 20 of (840-42x) ?
The integral from 0 to 20 of (840-42x) is 8400