What is the integral from 1 to 2 of 1/(sqrt(1+x)) ?

The integral from 1 to 2 of 1/(sqrt(1+x)) is 2sqrt(3)-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 2 of 1/(sqrt(1+x))

\int_{1}^{2} \frac{1}{1 + x} d x

23 - 22

Decimal

0.63567 \dots

Solution steps

\int_{1}^{2} \frac{1}{1 + x} d x

Apply u-substitution

= \int_{2}^{3} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{2}^{3}

Compute the boundaries:

23 - 22

= 23 - 22

What is the integral from 1 to 2 of 1/(sqrt(1+x)) ?
The integral from 1 to 2 of 1/(sqrt(1+x)) is 2sqrt(3)-2sqrt(2)