What is the integral from 1 to 7 of (3(ln(x))^2)/x ?

The integral from 1 to 7 of (3(ln(x))^2)/x is ln^3(7)

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integral from 1 to 7 of (3(ln(x))^2)/x

\int_{1}^{7} \frac{3 ( ln ( x ) ) ^{2}}{x} d x

ln^{3} (7)

Decimal

7.36831 \dots

Solution steps

\int_{1}^{7} \frac{3 ( ln ( x ) ) ^{2}}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{7} \frac{( ln ( x ) ) ^{2}}{x} d x

Apply u-substitution

= 3 \cdot \int_{0}^{l n (7)} u^{2} d u

Apply the Power Rule

= 3 [\frac{u ^{3}}{3}]_{0}^{l n (7)}

Compute the boundaries:

\frac{ln ^{3} ( 7 )}{3}

= 3 \cdot \frac{ln ^{3} ( 7 )}{3}

Simplify

= ln^{3} (7)

What is the integral from 1 to 7 of (3(ln(x))^2)/x ?
The integral from 1 to 7 of (3(ln(x))^2)/x is ln^3(7)