What is the integral from 0 to 3 of (x^2-4x+3) ?

The integral from 0 to 3 of (x^2-4x+3) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 3 of (x^2-4x+3)

\int_{0}^{3} (x^{2} - 4 x + 3) d x

0

Solution steps

\int_{0}^{3} x^{2} - 4 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{2} d x - \int_{0}^{3} 4 x d x + \int_{0}^{3} 3 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 4 x d x = 18

\int_{0}^{3} 3 d x = 9

= 9 - 18 + 9

Simplify

= 0

\int_{\frac{1}{2}}^{2} 1 - \frac{1}{x ^{2}} d x

\int_{0}^{1} (x^{4} + 3 x^{3} + 1) d x

\int_{- 5}^{4} 20 - x - x^{2} d x

\int_{2}^{3} c x d x

\int_{- 1}^{14} e^{- \frac{x}{2}} d x

What is the integral from 0 to 3 of (x^2-4x+3) ?
The integral from 0 to 3 of (x^2-4x+3) is 0