What is the derivative of 1+7sin(x-tan(x)) ?

The derivative of 1+7sin(x-tan(x)) is 7cos(x)-sec^2(x)

What is the first derivative of 1+7sin(x-tan(x)) ?

The first derivative of 1+7sin(x-tan(x)) is 7cos(x)-sec^2(x)

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\frac{d}{d x} (1 + 7 sin (x) - tan (x))

7 cos (x) - sec^{2} (x)

Solution steps

\frac{d}{d x} (1 + 7 sin (x) - tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (7 sin (x)) - \frac{d}{d x} (tan (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (7 sin (x)) = 7 cos (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 0 + 7 cos (x) - sec^{2} (x)

Simplify

= 7 cos (x) - sec^{2} (x)

What is the derivative of 1+7sin(x-tan(x)) ?
The derivative of 1+7sin(x-tan(x)) is 7cos(x)-sec^2(x)
What is the first derivative of 1+7sin(x-tan(x)) ?
The first derivative of 1+7sin(x-tan(x)) is 7cos(x)-sec^2(x)