What is the integral from x^2 to sqrt(x of)1 ?

The integral from x^2 to sqrt(x of)1 is sqrt(x)-x^2

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integral from x^2 to sqrt(x of)1

\int_{x^{2}}^{x} 1 d y

x - x^{2}

Solution steps

\int_{x^{2}}^{x} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x^{2}}^{x}

Simplify

= [y]_{x^{2}}^{x}

Compute the boundaries:

x - x^{2}

= x - x^{2}

What is the integral from x^2 to sqrt(x of)1 ?
The integral from x^2 to sqrt(x of)1 is sqrt(x)-x^2