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Popular Calculus >

integral from 0 to 3 of 3y-y^2

Solution

\int_{0}^{3} 3 y - y^{2} d y

Solution

\frac{9}{2}

+1

Decimal

4.5

Solution steps

\int_{0}^{3} 3 y - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 3 y d y - \int_{0}^{3} y^{2} d y

\int_{0}^{3} 3 y d y = \frac{27}{2}

\int_{0}^{3} y^{2} d y = 9

= \frac{27}{2} - 9

Simplify

\frac{27}{2} - 9 : \frac{9}{2}

= \frac{9}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of 3y-y^2 ?
The integral from 0 to 3 of 3y-y^2 is 9/2