What is the integral from-2 to 2 of (4x^4-3x^2+5) ?

The integral from-2 to 2 of (4x^4-3x^2+5) is 276/5

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integral from-2 to 2 of (4x^4-3x^2+5)

\int_{- 2}^{2} (4 x^{4} - 3 x^{2} + 5) d x

\frac{276}{5}

Decimal

55.2

Solution steps

\int_{- 2}^{2} 4 x^{4} - 3 x^{2} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 4 x^{4} d x - \int_{- 2}^{2} 3 x^{2} d x + \int_{- 2}^{2} 5 d x

\int_{- 2}^{2} 4 x^{4} d x = \frac{256}{5}

\int_{- 2}^{2} 3 x^{2} d x = 16

\int_{- 2}^{2} 5 d x = 20

= \frac{256}{5} - 16 + 20

Simplify

\frac{256}{5} - 16 + 20 : \frac{276}{5}

= \frac{276}{5}

What is the integral from-2 to 2 of (4x^4-3x^2+5) ?
The integral from-2 to 2 of (4x^4-3x^2+5) is 276/5