What is the integral from 0 to 1 of \sqrt[3]{1+7t} ?

The integral from 0 to 1 of \sqrt[3]{1+7t} is 45/28

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 1 of \sqrt[3]{1+7t}

\frac{45}{28}

Decimal

1.60714 \dots

Solution steps

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

= \frac{1}{7} [\frac{3}{4} u^{\frac{4}{3}}]_{1}^{8}

Compute the boundaries:

\frac{45}{4}

= \frac{1}{7} \cdot \frac{45}{4}

Simplify

= \frac{45}{28}

What is the integral from 0 to 1 of \sqrt[3]{1+7t} ?
The integral from 0 to 1 of \sqrt[3]{1+7t} is 45/28