What is the integral from-pi to 0 of sin(θ) ?

The integral from-pi to 0 of sin(θ) is -2

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integral from-pi to 0 of sin(θ)

\int_{- π}^{0} sin (θ) d θ

- 2

Solution steps

\int_{- π}^{0} sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{- π}^{0}

Compute the boundaries:

- 2

= - 2

What is the integral from-pi to 0 of sin(θ) ?
The integral from-pi to 0 of sin(θ) is -2