What is the integral from 1 to 1.5 of (2x+3/(2x^2)) ?

The integral from 1 to 1.5 of (2x+3/(2x^2)) is 1.75

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integral from 1 to 1.5 of (2x+3/(2x^2))

\int_{1}^{1.5} (2 x + \frac{3}{2 x ^{2}}) d x

1.75

Solution steps

\int_{1}^{1.5} 2 x + \frac{3}{2 x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{1.5} 2 x d x + \int_{1}^{1.5} \frac{3}{2 x ^{2}} d x

\int_{1}^{1.5} 2 x d x = 1.25

\int_{1}^{1.5} \frac{3}{2 x ^{2}} d x = 0.5

= 1.25 + 0.5

Simplify

= 1.75

What is the integral from 1 to 1.5 of (2x+3/(2x^2)) ?
The integral from 1 to 1.5 of (2x+3/(2x^2)) is 1.75