What is the integral from x to 1 of 1/(1+x^2) ?

The integral from x to 1 of 1/(1+x^2) is pi/4-arctan(x)

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integral from x to 1 of 1/(1+x^2)

\int_{x}^{1} \frac{1}{1 + x ^{2}} d x

\frac{π}{4} - arctan (x)

Solution steps

\int_{x}^{1} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{x}^{1}

Compute the boundaries:

\frac{π}{4} - arctan (x)

= \frac{π}{4} - arctan (x)

What is the integral from x to 1 of 1/(1+x^2) ?
The integral from x to 1 of 1/(1+x^2) is pi/4-arctan(x)