What is the integral from 4 to 16 of 1/(sqrt(z)) ?

The integral from 4 to 16 of 1/(sqrt(z)) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 4 to 16 of 1/(sqrt(z))

\int_{4}^{16} \frac{1}{z} d z

4

Solution steps

\int_{4}^{16} \frac{1}{z} d z

Apply the Power Rule

= [2 z^{\frac{1}{2}}]_{4}^{16}

Apply radical rule:

= [2 z]_{4}^{16}

Compute the boundaries:

4

= 4

What is the integral from 4 to 16 of 1/(sqrt(z)) ?
The integral from 4 to 16 of 1/(sqrt(z)) is 4