integral from 1 to 3 of 95+972t^2-18t

Lösung

\int_{1}^{3} 95 + 972 t^{2} - 18 t d t

8542

Schritte zur Lösung

\int_{1}^{3} 95 + 972 t^{2} - 18 t d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 95 d t + \int_{1}^{3} 972 t^{2} d t - \int_{1}^{3} 18 t d t

\int_{1}^{3} 95 d t = 190

\int_{1}^{3} 972 t^{2} d t = 8424

\int_{1}^{3} 18 t d t = 72

= 190 + 8424 - 72

Vereinfache

= 8542

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