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Popular Calculus >

integral from-1 to 4 of 16-x^2

Solution

\int_{- 1}^{4} 16 - x^{2} d x

Solution

\frac{175}{3}

+1

Decimal

58.33333 \dots

Solution steps

\int_{- 1}^{4} 16 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{4} 16 d x - \int_{- 1}^{4} x^{2} d x

\int_{- 1}^{4} 16 d x = 80

\int_{- 1}^{4} x^{2} d x = \frac{65}{3}

= 80 - \frac{65}{3}

Simplify

80 - \frac{65}{3} : \frac{175}{3}

= \frac{175}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 4 of 16-x^2 ?
The integral from-1 to 4 of 16-x^2 is 175/3