integral from 0 to b of (2^x+x^2)

Lösung

\int_{0}^{b} (2^{x} + x^{2}) d x

\frac{2 ^{b} - 1}{ln ( 2 )} + \frac{b ^{3}}{3}

Schritte zur Lösung

\int_{0}^{b} 2^{x} + x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{b} 2^{x} d x + \int_{0}^{b} x^{2} d x

\int_{0}^{b} 2^{x} d x = \frac{2 ^{b} - 1}{ln ( 2 )}

\int_{0}^{b} x^{2} d x = \frac{b ^{3}}{3}

= \frac{2 ^{b} - 1}{ln ( 2 )} + \frac{b ^{3}}{3}

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