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Popular Calculus >

integral from 0 to 2 of (1-x/2)

Solution

\int_{0}^{2} (1 - \frac{x}{2}) d x

Solution

1

Solution steps

\int_{0}^{2} 1 - \frac{x}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 1 d x - \int_{0}^{2} \frac{x}{2} d x

\int_{0}^{2} 1 d x = 2

\int_{0}^{2} \frac{x}{2} d x = 1

= 2 - 1

Simplify

= 1

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (1-x/2) ?
The integral from 0 to 2 of (1-x/2) is 1