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Popular Calculus >

integral from-1 to 1 of (3-|x|)

Solution

\int_{- 1}^{1} (3 - ∣ x ∣) d x

Solution

5

Solution steps

\int_{- 1}^{1} 3 - ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{0} 3 - (- x) d x + \int_{0}^{1} 3 - x d x

\int_{- 1}^{0} 3 - (- x) d x = \frac{5}{2}

\int_{0}^{1} 3 - x d x = \frac{5}{2}

= \frac{5}{2} + \frac{5}{2}

Simplify

\frac{5}{2} + \frac{5}{2} : 5

= 5

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (3-|x|) ?
The integral from-1 to 1 of (3-|x|) is 5