integral from 0 to 1/9 of x-9x^2

Lösung

\int_{0}^{\frac{1}{9}} x - 9 x^{2} d x

\frac{1}{486}

Dezimale

0.00205 \dots

Schritte zur Lösung

\int_{0}^{\frac{1}{9}} x - 9 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{1}{9}} x d x - \int_{0}^{\frac{1}{9}} 9 x^{2} d x

\int_{0}^{\frac{1}{9}} x d x = \frac{1}{162}

\int_{0}^{\frac{1}{9}} 9 x^{2} d x = \frac{1}{243}

= \frac{1}{162} - \frac{1}{243}

Vereinfache

\frac{1}{162} - \frac{1}{243} : \frac{1}{486}

= \frac{1}{486}

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