integral from-1 to 1 of x+y+1

Lösung

\int_{- 1}^{1} x + y + 1 d x

2 y + 2

Schritte zur Lösung

\int_{- 1}^{1} x + y + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 1 d x + \int_{- 1}^{1} y d x + \int_{- 1}^{1} x d x

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} y d x = 2 y

\int_{- 1}^{1} x d x = 0

= 2 + 2 y + 0

Vereinfache

= 2 y + 2

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